Factor
\left(n-4\right)\left(n^{2}+4n+16\right)
Evaluate
n^{3}-64
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\left(n-4\right)\left(n^{2}+4n+16\right)
Rewrite n^{3}-64 as n^{3}-4^{3}. The difference of cubes can be factored using the rule: a^{3}-b^{3}=\left(a-b\right)\left(a^{2}+ab+b^{2}\right). Polynomial n^{2}+4n+16 is not factored since it does not have any rational roots.
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