Solve n^2n*(-0.5m^3n^2)*2mn^2

$$n ^ { 2 } n \cdot ( - 0.5 m ^ { 3 } n ^ { 2 } ) \cdot 2 m n ^ { 2 }$$

Evaluate

$$-m^{4}n^{7}$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 2 and 1 to get 3.

$$n^{3}\left(-0.5\right)m^{3}n^{2}\times 2mn^{2}$$

To multiply powers of the same base, add their exponents. Add 3 and 2 to get 5.

$$n^{5}\left(-0.5\right)m^{3}\times 2mn^{2}$$

To multiply powers of the same base, add their exponents. Add 5 and 2 to get 7.

$$n^{7}\left(-0.5\right)m^{3}\times 2m$$

To multiply powers of the same base, add their exponents. Add 3 and 1 to get 4.

$$n^{7}\left(-0.5\right)m^{4}\times 2$$

Multiply -0.5 and 2 to get -1.

$$n^{7}\left(-1\right)m^{4}$$

Differentiate w.r.t. m

$$-4m^{3}n^{7}$$