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n^{2}-110n-1544=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
n=\frac{-\left(-110\right)±\sqrt{\left(-110\right)^{2}-4\left(-1544\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, -110 for b, and -1544 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
n=\frac{-\left(-110\right)±\sqrt{12100-4\left(-1544\right)}}{2}
Square -110.
n=\frac{-\left(-110\right)±\sqrt{12100+6176}}{2}
Multiply -4 times -1544.
n=\frac{-\left(-110\right)±\sqrt{18276}}{2}
Add 12100 to 6176.
n=\frac{-\left(-110\right)±2\sqrt{4569}}{2}
Take the square root of 18276.
n=\frac{110±2\sqrt{4569}}{2}
The opposite of -110 is 110.
n=\frac{2\sqrt{4569}+110}{2}
Now solve the equation n=\frac{110±2\sqrt{4569}}{2} when ± is plus. Add 110 to 2\sqrt{4569}.
n=\sqrt{4569}+55
Divide 110+2\sqrt{4569} by 2.
n=\frac{110-2\sqrt{4569}}{2}
Now solve the equation n=\frac{110±2\sqrt{4569}}{2} when ± is minus. Subtract 2\sqrt{4569} from 110.
n=55-\sqrt{4569}
Divide 110-2\sqrt{4569} by 2.
n=\sqrt{4569}+55 n=55-\sqrt{4569}
The equation is now solved.
n^{2}-110n-1544=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
n^{2}-110n-1544-\left(-1544\right)=-\left(-1544\right)
Add 1544 to both sides of the equation.
n^{2}-110n=-\left(-1544\right)
Subtracting -1544 from itself leaves 0.
n^{2}-110n=1544
Subtract -1544 from 0.
n^{2}-110n+\left(-55\right)^{2}=1544+\left(-55\right)^{2}
Divide -110, the coefficient of the x term, by 2 to get -55. Then add the square of -55 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
n^{2}-110n+3025=1544+3025
Square -55.
n^{2}-110n+3025=4569
Add 1544 to 3025.
\left(n-55\right)^{2}=4569
Factor n^{2}-110n+3025. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(n-55\right)^{2}}=\sqrt{4569}
Take the square root of both sides of the equation.
n-55=\sqrt{4569} n-55=-\sqrt{4569}
Simplify.
n=\sqrt{4569}+55 n=55-\sqrt{4569}
Add 55 to both sides of the equation.
x ^ 2 -110x -1544 = 0
Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.
r + s = 110 rs = -1544
Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C
r = 55 - u s = 55 + u
Two numbers r and s sum up to 110 exactly when the average of the two numbers is \frac{1}{2}*110 = 55. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>
(55 - u) (55 + u) = -1544
To solve for unknown quantity u, substitute these in the product equation rs = -1544
3025 - u^2 = -1544
Simplify by expanding (a -b) (a + b) = a^2 – b^2
-u^2 = -1544-3025 = -4569
Simplify the expression by subtracting 3025 on both sides
u^2 = 4569 u = \pm\sqrt{4569} = \pm \sqrt{4569}
Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u
r =55 - \sqrt{4569} = -12.594 s = 55 + \sqrt{4569} = 122.594
The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.