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n^{2}-100=0
Subtract 100 from both sides.
\left(n-10\right)\left(n+10\right)=0
Consider n^{2}-100. Rewrite n^{2}-100 as n^{2}-10^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
n=10 n=-10
To find equation solutions, solve n-10=0 and n+10=0.
n=10 n=-10
Take the square root of both sides of the equation.
n^{2}-100=0
Subtract 100 from both sides.
n=\frac{0±\sqrt{0^{2}-4\left(-100\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -100 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
n=\frac{0±\sqrt{-4\left(-100\right)}}{2}
Square 0.
n=\frac{0±\sqrt{400}}{2}
Multiply -4 times -100.
n=\frac{0±20}{2}
Take the square root of 400.
n=10
Now solve the equation n=\frac{0±20}{2} when ± is plus. Divide 20 by 2.
n=-10
Now solve the equation n=\frac{0±20}{2} when ± is minus. Divide -20 by 2.
n=10 n=-10
The equation is now solved.