Solve n^2+8n-n8=0

$$n ^ { 2 } + 8 n - n 8 = 0$$

Solve for n_8

$$n_{8}=n\left(n+8\right)$$

Steps for Solving Linear Equation

Subtract n^{2} from both sides. Anything subtracted from zero gives its negation.

$$8n-n_{8}=-n^{2}$$

Subtract 8n from both sides.

$$-n_{8}=-n^{2}-8n$$

Divide both sides by -1.

$$\frac{-n_{8}}{-1}=-\frac{n\left(n+8\right)}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$n_{8}=-\frac{n\left(n+8\right)}{-1}$$

Divide -n\left(8+n\right) by -1.

$$n_{8}=n\left(n+8\right)$$

Solve for n (complex solution)

$$n=\sqrt{n_{8}+16}-4$$

$$n=-\sqrt{n_{8}+16}-4$$

Solve for n

$$n=\sqrt{n_{8}+16}-4$$

$$n=-\sqrt{n_{8}+16}-4\text{, }n_{8}\geq -16$$