Skip to main content
Solve for n
Tick mark Image

Similar Problems from Web Search

Share

n^{2}+200n-5399=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
n=\frac{-200±\sqrt{200^{2}-4\left(-5399\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 200 for b, and -5399 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
n=\frac{-200±\sqrt{40000-4\left(-5399\right)}}{2}
Square 200.
n=\frac{-200±\sqrt{40000+21596}}{2}
Multiply -4 times -5399.
n=\frac{-200±\sqrt{61596}}{2}
Add 40000 to 21596.
n=\frac{-200±6\sqrt{1711}}{2}
Take the square root of 61596.
n=\frac{6\sqrt{1711}-200}{2}
Now solve the equation n=\frac{-200±6\sqrt{1711}}{2} when ± is plus. Add -200 to 6\sqrt{1711}.
n=3\sqrt{1711}-100
Divide -200+6\sqrt{1711} by 2.
n=\frac{-6\sqrt{1711}-200}{2}
Now solve the equation n=\frac{-200±6\sqrt{1711}}{2} when ± is minus. Subtract 6\sqrt{1711} from -200.
n=-3\sqrt{1711}-100
Divide -200-6\sqrt{1711} by 2.
n=3\sqrt{1711}-100 n=-3\sqrt{1711}-100
The equation is now solved.
n^{2}+200n-5399=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
n^{2}+200n-5399-\left(-5399\right)=-\left(-5399\right)
Add 5399 to both sides of the equation.
n^{2}+200n=-\left(-5399\right)
Subtracting -5399 from itself leaves 0.
n^{2}+200n=5399
Subtract -5399 from 0.
n^{2}+200n+100^{2}=5399+100^{2}
Divide 200, the coefficient of the x term, by 2 to get 100. Then add the square of 100 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
n^{2}+200n+10000=5399+10000
Square 100.
n^{2}+200n+10000=15399
Add 5399 to 10000.
\left(n+100\right)^{2}=15399
Factor n^{2}+200n+10000. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(n+100\right)^{2}}=\sqrt{15399}
Take the square root of both sides of the equation.
n+100=3\sqrt{1711} n+100=-3\sqrt{1711}
Simplify.
n=3\sqrt{1711}-100 n=-3\sqrt{1711}-100
Subtract 100 from both sides of the equation.
x ^ 2 +200x -5399 = 0
Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.
r + s = -200 rs = -5399
Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C
r = -100 - u s = -100 + u
Two numbers r and s sum up to -200 exactly when the average of the two numbers is \frac{1}{2}*-200 = -100. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>
(-100 - u) (-100 + u) = -5399
To solve for unknown quantity u, substitute these in the product equation rs = -5399
10000 - u^2 = -5399
Simplify by expanding (a -b) (a + b) = a^2 – b^2
-u^2 = -5399-10000 = -15399
Simplify the expression by subtracting 10000 on both sides
u^2 = 15399 u = \pm\sqrt{15399} = \pm \sqrt{15399}
Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u
r =-100 - \sqrt{15399} = -224.093 s = -100 + \sqrt{15399} = 24.093
The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.