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n\left(n+13\right)=0
Factor out n.
n=0 n=-13
To find equation solutions, solve n=0 and n+13=0.
n^{2}+13n=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
n=\frac{-13±\sqrt{13^{2}}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 13 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
n=\frac{-13±13}{2}
Take the square root of 13^{2}.
n=\frac{0}{2}
Now solve the equation n=\frac{-13±13}{2} when ± is plus. Add -13 to 13.
n=0
Divide 0 by 2.
n=-\frac{26}{2}
Now solve the equation n=\frac{-13±13}{2} when ± is minus. Subtract 13 from -13.
n=-13
Divide -26 by 2.
n=0 n=-13
The equation is now solved.
n^{2}+13n=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
n^{2}+13n+\left(\frac{13}{2}\right)^{2}=\left(\frac{13}{2}\right)^{2}
Divide 13, the coefficient of the x term, by 2 to get \frac{13}{2}. Then add the square of \frac{13}{2} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
n^{2}+13n+\frac{169}{4}=\frac{169}{4}
Square \frac{13}{2} by squaring both the numerator and the denominator of the fraction.
\left(n+\frac{13}{2}\right)^{2}=\frac{169}{4}
Factor n^{2}+13n+\frac{169}{4}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(n+\frac{13}{2}\right)^{2}}=\sqrt{\frac{169}{4}}
Take the square root of both sides of the equation.
n+\frac{13}{2}=\frac{13}{2} n+\frac{13}{2}=-\frac{13}{2}
Simplify.
n=0 n=-13
Subtract \frac{13}{2} from both sides of the equation.