Solve for n
n=\frac{-11+11\sqrt{7}i}{2}\approx -5.5+14.551632211i
n=\frac{-11\sqrt{7}i-11}{2}\approx -5.5-14.551632211i
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n^{2}+11n+242=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
n=\frac{-11±\sqrt{11^{2}-4\times 242}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 11 for b, and 242 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
n=\frac{-11±\sqrt{121-4\times 242}}{2}
Square 11.
n=\frac{-11±\sqrt{121-968}}{2}
Multiply -4 times 242.
n=\frac{-11±\sqrt{-847}}{2}
Add 121 to -968.
n=\frac{-11±11\sqrt{7}i}{2}
Take the square root of -847.
n=\frac{-11+11\sqrt{7}i}{2}
Now solve the equation n=\frac{-11±11\sqrt{7}i}{2} when ± is plus. Add -11 to 11i\sqrt{7}.
n=\frac{-11\sqrt{7}i-11}{2}
Now solve the equation n=\frac{-11±11\sqrt{7}i}{2} when ± is minus. Subtract 11i\sqrt{7} from -11.
n=\frac{-11+11\sqrt{7}i}{2} n=\frac{-11\sqrt{7}i-11}{2}
The equation is now solved.
n^{2}+11n+242=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
n^{2}+11n+242-242=-242
Subtract 242 from both sides of the equation.
n^{2}+11n=-242
Subtracting 242 from itself leaves 0.
n^{2}+11n+\left(\frac{11}{2}\right)^{2}=-242+\left(\frac{11}{2}\right)^{2}
Divide 11, the coefficient of the x term, by 2 to get \frac{11}{2}. Then add the square of \frac{11}{2} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
n^{2}+11n+\frac{121}{4}=-242+\frac{121}{4}
Square \frac{11}{2} by squaring both the numerator and the denominator of the fraction.
n^{2}+11n+\frac{121}{4}=-\frac{847}{4}
Add -242 to \frac{121}{4}.
\left(n+\frac{11}{2}\right)^{2}=-\frac{847}{4}
Factor n^{2}+11n+\frac{121}{4}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(n+\frac{11}{2}\right)^{2}}=\sqrt{-\frac{847}{4}}
Take the square root of both sides of the equation.
n+\frac{11}{2}=\frac{11\sqrt{7}i}{2} n+\frac{11}{2}=-\frac{11\sqrt{7}i}{2}
Simplify.
n=\frac{-11+11\sqrt{7}i}{2} n=\frac{-11\sqrt{7}i-11}{2}
Subtract \frac{11}{2} from both sides of the equation.
x ^ 2 +11x +242 = 0
Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.
r + s = -11 rs = 242
Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C
r = -\frac{11}{2} - u s = -\frac{11}{2} + u
Two numbers r and s sum up to -11 exactly when the average of the two numbers is \frac{1}{2}*-11 = -\frac{11}{2}. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>
(-\frac{11}{2} - u) (-\frac{11}{2} + u) = 242
To solve for unknown quantity u, substitute these in the product equation rs = 242
\frac{121}{4} - u^2 = 242
Simplify by expanding (a -b) (a + b) = a^2 – b^2
-u^2 = 242-\frac{121}{4} = \frac{847}{4}
Simplify the expression by subtracting \frac{121}{4} on both sides
u^2 = -\frac{847}{4} u = \pm\sqrt{-\frac{847}{4}} = \pm \frac{\sqrt{847}}{2}i
Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u
r =-\frac{11}{2} - \frac{\sqrt{847}}{2}i = -5.500 - 14.552i s = -\frac{11}{2} + \frac{\sqrt{847}}{2}i = -5.500 + 14.552i
The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.
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