Factor
\left(n+1\right)\left(n+9\right)
Evaluate
\left(n+1\right)\left(n+9\right)
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a+b=10 ab=1\times 9=9
Factor the expression by grouping. First, the expression needs to be rewritten as n^{2}+an+bn+9. To find a and b, set up a system to be solved.
1,9 3,3
Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 9.
1+9=10 3+3=6
Calculate the sum for each pair.
a=1 b=9
The solution is the pair that gives sum 10.
\left(n^{2}+n\right)+\left(9n+9\right)
Rewrite n^{2}+10n+9 as \left(n^{2}+n\right)+\left(9n+9\right).
n\left(n+1\right)+9\left(n+1\right)
Factor out n in the first and 9 in the second group.
\left(n+1\right)\left(n+9\right)
Factor out common term n+1 by using distributive property.
n^{2}+10n+9=0
Quadratic polynomial can be factored using the transformation ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), where x_{1} and x_{2} are the solutions of the quadratic equation ax^{2}+bx+c=0.
n=\frac{-10±\sqrt{10^{2}-4\times 9}}{2}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
n=\frac{-10±\sqrt{100-4\times 9}}{2}
Square 10.
n=\frac{-10±\sqrt{100-36}}{2}
Multiply -4 times 9.
n=\frac{-10±\sqrt{64}}{2}
Add 100 to -36.
n=\frac{-10±8}{2}
Take the square root of 64.
n=-\frac{2}{2}
Now solve the equation n=\frac{-10±8}{2} when ± is plus. Add -10 to 8.
n=-1
Divide -2 by 2.
n=-\frac{18}{2}
Now solve the equation n=\frac{-10±8}{2} when ± is minus. Subtract 8 from -10.
n=-9
Divide -18 by 2.
n^{2}+10n+9=\left(n-\left(-1\right)\right)\left(n-\left(-9\right)\right)
Factor the original expression using ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Substitute -1 for x_{1} and -9 for x_{2}.
n^{2}+10n+9=\left(n+1\right)\left(n+9\right)
Simplify all the expressions of the form p-\left(-q\right) to p+q.
x ^ 2 +10x +9 = 0
Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.
r + s = -10 rs = 9
Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C
r = -5 - u s = -5 + u
Two numbers r and s sum up to -10 exactly when the average of the two numbers is \frac{1}{2}*-10 = -5. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>
(-5 - u) (-5 + u) = 9
To solve for unknown quantity u, substitute these in the product equation rs = 9
25 - u^2 = 9
Simplify by expanding (a -b) (a + b) = a^2 – b^2
-u^2 = 9-25 = -16
Simplify the expression by subtracting 25 on both sides
u^2 = 16 u = \pm\sqrt{16} = \pm 4
Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u
r =-5 - 4 = -9 s = -5 + 4 = -1
The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.
Examples
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{ x } ^ { 2 } - 4 x - 5 = 0
Trigonometry
4 \sin \theta \cos \theta = 2 \sin \theta
Linear equation
y = 3x + 4
Arithmetic
699 * 533
Matrix
\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Limits
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}