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n ^ {-1} \frac{5}{13} + 0.9999451693655121 ^ {-1} = 0.0688307304338548 ^ {-1}
Evaluate trigonometric functions in the problem
n^{-1}\times \frac{5}{13}+\frac{10000000000000000}{9999451693655121}=0.0688307304338548^{-1}
Calculate 0.9999451693655121 to the power of -1 and get \frac{10000000000000000}{9999451693655121}.
n^{-1}\times \frac{5}{13}+\frac{10000000000000000}{9999451693655121}=\frac{2500000000000000}{172076826084637}
Calculate 0.0688307304338548 to the power of -1 and get \frac{2500000000000000}{172076826084637}.
n^{-1}\times \frac{5}{13}=\frac{2500000000000000}{172076826084637}-\frac{10000000000000000}{9999451693655121}
Subtract \frac{10000000000000000}{9999451693655121} from both sides.
n^{-1}\times \frac{5}{13}=\frac{23277860973291432500000000000000}{1720673910030821153321834476077}
Subtract \frac{10000000000000000}{9999451693655121} from \frac{2500000000000000}{172076826084637} to get \frac{23277860973291432500000000000000}{1720673910030821153321834476077}.
n^{-1}=\frac{23277860973291432500000000000000}{1720673910030821153321834476077}\times \frac{13}{5}
Multiply both sides by \frac{13}{5}, the reciprocal of \frac{5}{13}.
n^{-1}=\frac{60522438530557724500000000000000}{1720673910030821153321834476077}
Multiply \frac{23277860973291432500000000000000}{1720673910030821153321834476077} and \frac{13}{5} to get \frac{60522438530557724500000000000000}{1720673910030821153321834476077}.
\frac{1}{n}=\frac{60522438530557724500000000000000}{1720673910030821153321834476077}
Reorder the terms.
1720673910030821153321834476077=60522438530557724500000000000000n
Variable n cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 1720673910030821153321834476077n, the least common multiple of n,1720673910030821153321834476077.
60522438530557724500000000000000n=1720673910030821153321834476077
Swap sides so that all variable terms are on the left hand side.
n=\frac{1720673910030821153321834476077}{60522438530557724500000000000000}
Divide both sides by 60522438530557724500000000000000.