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Solve for n
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n=\frac{1}{8}+\frac{3}{8}-\frac{6\times 2+1}{2}\times \frac{2}{13}es
Calculate 2 to the power of -3 and get \frac{1}{8}.
n=\frac{1}{2}-\frac{6\times 2+1}{2}\times \frac{2}{13}es
Add \frac{1}{8} and \frac{3}{8} to get \frac{1}{2}.
n=\frac{1}{2}-\frac{12+1}{2}\times \frac{2}{13}es
Multiply 6 and 2 to get 12.
n=\frac{1}{2}-\frac{13}{2}\times \frac{2}{13}es
Add 12 and 1 to get 13.
n=\frac{1}{2}-es
Multiply \frac{13}{2} and \frac{2}{13} to get 1.
n=-es+\frac{1}{2}
Reorder the terms.
n=\frac{1}{8}+\frac{3}{8}-\frac{6\times 2+1}{2}\times \frac{2}{13}es
Calculate 2 to the power of -3 and get \frac{1}{8}.
n=\frac{1}{2}-\frac{6\times 2+1}{2}\times \frac{2}{13}es
Add \frac{1}{8} and \frac{3}{8} to get \frac{1}{2}.
n=\frac{1}{2}-\frac{12+1}{2}\times \frac{2}{13}es
Multiply 6 and 2 to get 12.
n=\frac{1}{2}-\frac{13}{2}\times \frac{2}{13}es
Add 12 and 1 to get 13.
n=\frac{1}{2}-es
Multiply \frac{13}{2} and \frac{2}{13} to get 1.
\frac{1}{2}-es=n
Swap sides so that all variable terms are on the left hand side.
-es=n-\frac{1}{2}
Subtract \frac{1}{2} from both sides.
\left(-e\right)s=n-\frac{1}{2}
The equation is in standard form.
\frac{\left(-e\right)s}{-e}=\frac{n-\frac{1}{2}}{-e}
Divide both sides by -e.
s=\frac{n-\frac{1}{2}}{-e}
Dividing by -e undoes the multiplication by -e.
s=-\frac{2n-1}{2e}
Divide n-\frac{1}{2} by -e.