Solve mx^2-2mx+4=0

$$m x ^ { 2 } - 2 m x + 4 = 0$$

Solve for m

$$m=-\frac{4}{x\left(x-2\right)}$$

$$x\neq 2\text{ and }x\neq 0$$

Steps for Solving Linear Equation

Subtract 4 from both sides. Anything subtracted from zero gives its negation.

$$mx^{2}-2mx=-4$$

Combine all terms containing m.

$$\left(x^{2}-2x\right)m=-4$$

Divide both sides by x^{2}-2x.

$$\frac{\left(x^{2}-2x\right)m}{x^{2}-2x}=-\frac{4}{x^{2}-2x}$$

Dividing by x^{2}-2x undoes the multiplication by x^{2}-2x.

$$m=-\frac{4}{x^{2}-2x}$$

Divide -4 by x^{2}-2x.

$$m=-\frac{4}{x\left(x-2\right)}$$

Solve for x (complex solution)

$$x=\frac{\sqrt{m\left(m-4\right)}+m}{m}$$

$$x=\frac{-\sqrt{m\left(m-4\right)}+m}{m}\text{, }m\neq 0$$

Solve for x

$$x=\frac{\sqrt{m\left(m-4\right)}+m}{m}$$

$$x=\frac{-\sqrt{m\left(m-4\right)}+m}{m}\text{, }m<0\text{ or }m\geq 4$$