Solve m_{3}-0.28N_{2}=100

$$m _ { 3 } - 0.28 N _ { 2 } = 100$$

Solve for N_2

$$N_{2}=\frac{25m_{3}-2500}{7}$$

Steps for Solving Linear Equation

Subtract m_{3} from both sides.

$$-0.28N_{2}=100-m_{3}$$

Divide both sides of the equation by -0.28, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{-0.28N_{2}}{-0.28}=\frac{100-m_{3}}{-0.28}$$

Dividing by -0.28 undoes the multiplication by -0.28.

$$N_{2}=\frac{100-m_{3}}{-0.28}$$

Divide 100-m_{3} by -0.28 by multiplying 100-m_{3} by the reciprocal of -0.28.

$$N_{2}=\frac{25m_{3}-2500}{7}$$

Solve for m_3

$$m_{3}=\frac{7N_{2}}{25}+100$$

Solution Steps

Add 0.28N_{2} to both sides.

$$m_{3}=100+0.28N_{2}$$