Solve m(m-3)-2m(m-4)=-(m^2-4m)+6

$$m ( m - 3 ) - 2 m ( m - 4 ) = - ( m ^ { 2 } - 4 m ) + 6$$

Solve for m

$$m=6$$

Steps for Solving Linear Equation

Use the distributive property to multiply m by m-3.

$$m^{2}-3m-2m\left(m-4\right)=-\left(m^{2}-4m\right)+6$$

To find the opposite of m^{2}-4m, find the opposite of each term.

$$m^{2}-3m-2m\left(m-4\right)=-m^{2}+4m+6$$

Add m^{2} to both sides.

$$m^{2}-3m-2m\left(m-4\right)+m^{2}=4m+6$$

Subtract 4m from both sides.

$$m^{2}-3m-2m\left(m-4\right)+m^{2}-4m=6$$

Use the distributive property to multiply -2m by m-4.

$$m^{2}-3m-2m^{2}+8m+m^{2}-4m=6$$

Combine m^{2} and -2m^{2} to get -m^{2}.

$$-m^{2}-3m+8m+m^{2}-4m=6$$

Combine -3m and 8m to get 5m.

$$-m^{2}+5m+m^{2}-4m=6$$

Combine -m^{2} and m^{2} to get 0.

$$5m-4m=6$$

Combine 5m and -4m to get m.

$$m=6$$