Solve for m
m=3x-\frac{3}{2}
Solve for x
x=\frac{m}{3}+\frac{1}{2}
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m\times 2+3=6x
Add 6x to both sides. Anything plus zero gives itself.
m\times 2=6x-3
Subtract 3 from both sides.
2m=6x-3
The equation is in standard form.
\frac{2m}{2}=\frac{6x-3}{2}
Divide both sides by 2.
m=\frac{6x-3}{2}
Dividing by 2 undoes the multiplication by 2.
m=3x-\frac{3}{2}
Divide 6x-3 by 2.
-6x+3=-m\times 2
Subtract m\times 2 from both sides. Anything subtracted from zero gives its negation.
-6x=-m\times 2-3
Subtract 3 from both sides.
-6x=-2m-3
Multiply -1 and 2 to get -2.
\frac{-6x}{-6}=\frac{-2m-3}{-6}
Divide both sides by -6.
x=\frac{-2m-3}{-6}
Dividing by -6 undoes the multiplication by -6.
x=\frac{m}{3}+\frac{1}{2}
Divide -2m-3 by -6.
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Limits
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