Solve for n
n=\frac{m^{3}-25}{2}
Solve for m
m=\sqrt[3]{2n+25}
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-2n=25-m^{3}
Subtract m^{3} from both sides.
\frac{-2n}{-2}=\frac{25-m^{3}}{-2}
Divide both sides by -2.
n=\frac{25-m^{3}}{-2}
Dividing by -2 undoes the multiplication by -2.
n=\frac{m^{3}-25}{2}
Divide 25-m^{3} by -2.
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