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m\left(m^{2}-13m+30\right)
Factor out m.
a+b=-13 ab=1\times 30=30
Consider m^{2}-13m+30. Factor the expression by grouping. First, the expression needs to be rewritten as m^{2}+am+bm+30. To find a and b, set up a system to be solved.
-1,-30 -2,-15 -3,-10 -5,-6
Since ab is positive, a and b have the same sign. Since a+b is negative, a and b are both negative. List all such integer pairs that give product 30.
-1-30=-31 -2-15=-17 -3-10=-13 -5-6=-11
Calculate the sum for each pair.
a=-10 b=-3
The solution is the pair that gives sum -13.
\left(m^{2}-10m\right)+\left(-3m+30\right)
Rewrite m^{2}-13m+30 as \left(m^{2}-10m\right)+\left(-3m+30\right).
m\left(m-10\right)-3\left(m-10\right)
Factor out m in the first and -3 in the second group.
\left(m-10\right)\left(m-3\right)
Factor out common term m-10 by using distributive property.
m\left(m-10\right)\left(m-3\right)
Rewrite the complete factored expression.