Factor
\frac{\left(5m-2\right)\left(25m^{2}+10m+4\right)}{125}
Evaluate
m^{3}-\frac{8}{125}
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\frac{125m^{3}-8}{125}
Factor out \frac{1}{125}.
\left(5m-2\right)\left(25m^{2}+10m+4\right)
Consider 125m^{3}-8. Rewrite 125m^{3}-8 as \left(5m\right)^{3}-2^{3}. The difference of cubes can be factored using the rule: a^{3}-b^{3}=\left(a-b\right)\left(a^{2}+ab+b^{2}\right).
\frac{\left(5m-2\right)\left(25m^{2}+10m+4\right)}{125}
Rewrite the complete factored expression. Polynomial 25m^{2}+10m+4 is not factored since it does not have any rational roots.
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