Solve m^2-m-2=(m-5)^2+36

$$m ^ { 2 } - m - 2 = ( m - 5 ) ^ { 2 } + 36$$

Solve for m

$$m=7$$

Steps for Solving Linear Equation

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(m-5\right)^{2}.

$$m^{2}-m-2=m^{2}-10m+25+36$$

Add 25 and 36 to get 61.

$$m^{2}-m-2=m^{2}-10m+61$$

Subtract m^{2} from both sides.

$$m^{2}-m-2-m^{2}=-10m+61$$

Combine m^{2} and -m^{2} to get 0.

$$-m-2=-10m+61$$

Add 10m to both sides.

$$-m-2+10m=61$$

Combine -m and 10m to get 9m.

$$9m-2=61$$

Add 2 to both sides.

$$9m=61+2$$

Add 61 and 2 to get 63.

$$9m=63$$

Divide both sides by 9.

$$m=\frac{63}{9}$$

Divide 63 by 9 to get 7.

$$m=7$$