Solve m^2-9+2/m+3=

$$m ^ { 2 } - 9 + \frac { 2 } { m + 3 } =$$

Evaluate

$$\frac{m^{3}+3m^{2}-9m-25}{m+3}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply m^{2}-9 times \frac{m+3}{m+3}.

$$\frac{\left(m^{2}-9\right)\left(m+3\right)}{m+3}+\frac{2}{m+3}$$

Since \frac{\left(m^{2}-9\right)\left(m+3\right)}{m+3} and \frac{2}{m+3} have the same denominator, add them by adding their numerators.

$$\frac{\left(m^{2}-9\right)\left(m+3\right)+2}{m+3}$$

Do the multiplications in \left(m^{2}-9\right)\left(m+3\right)+2.

$$\frac{m^{3}+3m^{2}-9m-27+2}{m+3}$$

Combine like terms in m^{3}+3m^{2}-9m-27+2.

$$\frac{m^{3}+3m^{2}-9m-25}{m+3}$$

Differentiate w.r.t. m

$$\frac{2\left(m^{3}+6m^{2}+9m-1\right)}{\left(m+3\right)^{2}}$$