Solve m^2-7+0=0

$$m ^ { 2 } - 7 + 0 = 0$$

Solve for m

$$m=\sqrt{7}\approx 2.645751311$$

$$m=-\sqrt{7}\approx -2.645751311$$

Steps by Finding Square Root

Add -7 and 0 to get -7.

$$m^{2}-7=0$$

Add 7 to both sides. Anything plus zero gives itself.

$$m^{2}=7$$

Take the square root of both sides of the equation.

$$m=\sqrt{7} m=-\sqrt{7}$$

Steps Using the Quadratic Formula

Add -7 and 0 to get -7.

$$m^{2}-7=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -7 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$m=\frac{0±\sqrt{0^{2}-4\left(-7\right)}}{2}$$

Square 0.

$$m=\frac{0±\sqrt{-4\left(-7\right)}}{2}$$

Multiply -4 times -7.

$$m=\frac{0±\sqrt{28}}{2}$$

Take the square root of 28.

$$m=\frac{0±2\sqrt{7}}{2}$$

Now solve the equation m=\frac{0±2\sqrt{7}}{2} when ± is plus.

$$m=\sqrt{7}$$

Now solve the equation m=\frac{0±2\sqrt{7}}{2} when ± is minus.

$$m=-\sqrt{7}$$

The equation is now solved.

$$m=\sqrt{7} m=-\sqrt{7}$$