Solve m^2-4-0=0

$$m ^ { 2 } - 4 - 0 = 0$$

Solve for m

$$m=2$$

$$m=-2$$

Steps Using Difference of Squares

Reorder the terms.

$$m^{2}-4=0$$

Consider m^{2}-4. Rewrite m^{2}-4 as m^{2}-2^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(m-2\right)\left(m+2\right)=0$$

To find equation solutions, solve m-2=0 and m+2=0.

$$m=2 m=-2$$

Steps by Finding Square Root

Add 0 to both sides.

$$m^{2}-4=0+0$$

Add 0 and 0 to get 0.

$$m^{2}-4=0$$

Add 4 to both sides. Anything plus zero gives itself.

$$m^{2}=4$$

Take the square root of both sides of the equation.

$$m=2 m=-2$$

Steps Using the Quadratic Formula

Reorder the terms.

$$m^{2}-4=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -4 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$m=\frac{0±\sqrt{0^{2}-4\left(-4\right)}}{2}$$

Square 0.

$$m=\frac{0±\sqrt{-4\left(-4\right)}}{2}$$

Multiply -4 times -4.

$$m=\frac{0±\sqrt{16}}{2}$$

Take the square root of 16.

$$m=\frac{0±4}{2}$$

Now solve the equation m=\frac{0±4}{2} when ± is plus. Divide 4 by 2.

$$m=2$$

Now solve the equation m=\frac{0±4}{2} when ± is minus. Divide -4 by 2.

$$m=-2$$

The equation is now solved.

$$m=2 m=-2$$