Solve m^2-3-7n+342=0

$$m ^ { 2 } - 3 - 7 n + 342 = 0$$

Solve for n

$$n=\frac{m^{2}+339}{7}$$

Steps for Solving Linear Equation

Add -3 and 342 to get 339.

$$m^{2}+339-7n=0$$

Subtract m^{2} from both sides. Anything subtracted from zero gives its negation.

$$339-7n=-m^{2}$$

Subtract 339 from both sides.

$$-7n=-m^{2}-339$$

Divide both sides by -7.

$$\frac{-7n}{-7}=\frac{-m^{2}-339}{-7}$$

Dividing by -7 undoes the multiplication by -7.

$$n=\frac{-m^{2}-339}{-7}$$

Divide -m^{2}-339 by -7.

$$n=\frac{m^{2}+339}{7}$$

Solve for m

$$m=\sqrt{7n-339}$$

$$m=-\sqrt{7n-339}\text{, }n\geq \frac{339}{7}$$