Solve m^2-2y=-2m

$$m ^ { 2 } - 2 y = - 2 m$$

Solve for y

$$y=\frac{m\left(m+2\right)}{2}$$

Steps for Solving Linear Equation

Subtract m^{2} from both sides.

$$-2y=-2m-m^{2}$$

The equation is in standard form.

$$-2y=-m^{2}-2m$$

Divide both sides by -2.

$$\frac{-2y}{-2}=-\frac{m\left(m+2\right)}{-2}$$

Dividing by -2 undoes the multiplication by -2.

$$y=-\frac{m\left(m+2\right)}{-2}$$

Divide -m\left(2+m\right) by -2.

$$y=\frac{m\left(m+2\right)}{2}$$

Solve for m (complex solution)

$$m=\sqrt{2y+1}-1$$

$$m=-\sqrt{2y+1}-1$$

Solve for m

$$m=\sqrt{2y+1}-1$$

$$m=-\sqrt{2y+1}-1\text{, }y\geq -\frac{1}{2}$$