Solve m^2-2h+5=0

$$m ^ { 2 } - 2 h + 5 = 0$$

Solve for h

$$h=\frac{m^{2}+5}{2}$$

Steps for Solving Linear Equation

Subtract m^{2} from both sides. Anything subtracted from zero gives its negation.

$$-2h+5=-m^{2}$$

Subtract 5 from both sides.

$$-2h=-m^{2}-5$$

Divide both sides by -2.

$$\frac{-2h}{-2}=\frac{-m^{2}-5}{-2}$$

Dividing by -2 undoes the multiplication by -2.

$$h=\frac{-m^{2}-5}{-2}$$

Divide -m^{2}-5 by -2.

$$h=\frac{m^{2}+5}{2}$$

Solve for m

$$m=\sqrt{2h-5}$$

$$m=-\sqrt{2h-5}\text{, }h\geq \frac{5}{2}$$