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a+b=-13 ab=1\left(-30\right)=-30
Factor the expression by grouping. First, the expression needs to be rewritten as m^{2}+am+bm-30. To find a and b, set up a system to be solved.
1,-30 2,-15 3,-10 5,-6
Since ab is negative, a and b have the opposite signs. Since a+b is negative, the negative number has greater absolute value than the positive. List all such integer pairs that give product -30.
1-30=-29 2-15=-13 3-10=-7 5-6=-1
Calculate the sum for each pair.
a=-15 b=2
The solution is the pair that gives sum -13.
\left(m^{2}-15m\right)+\left(2m-30\right)
Rewrite m^{2}-13m-30 as \left(m^{2}-15m\right)+\left(2m-30\right).
m\left(m-15\right)+2\left(m-15\right)
Factor out m in the first and 2 in the second group.
\left(m-15\right)\left(m+2\right)
Factor out common term m-15 by using distributive property.
m^{2}-13m-30=0
Quadratic polynomial can be factored using the transformation ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), where x_{1} and x_{2} are the solutions of the quadratic equation ax^{2}+bx+c=0.
m=\frac{-\left(-13\right)±\sqrt{\left(-13\right)^{2}-4\left(-30\right)}}{2}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
m=\frac{-\left(-13\right)±\sqrt{169-4\left(-30\right)}}{2}
Square -13.
m=\frac{-\left(-13\right)±\sqrt{169+120}}{2}
Multiply -4 times -30.
m=\frac{-\left(-13\right)±\sqrt{289}}{2}
Add 169 to 120.
m=\frac{-\left(-13\right)±17}{2}
Take the square root of 289.
m=\frac{13±17}{2}
The opposite of -13 is 13.
m=\frac{30}{2}
Now solve the equation m=\frac{13±17}{2} when ± is plus. Add 13 to 17.
m=15
Divide 30 by 2.
m=-\frac{4}{2}
Now solve the equation m=\frac{13±17}{2} when ± is minus. Subtract 17 from 13.
m=-2
Divide -4 by 2.
m^{2}-13m-30=\left(m-15\right)\left(m-\left(-2\right)\right)
Factor the original expression using ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Substitute 15 for x_{1} and -2 for x_{2}.
m^{2}-13m-30=\left(m-15\right)\left(m+2\right)
Simplify all the expressions of the form p-\left(-q\right) to p+q.
x ^ 2 -13x -30 = 0
Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.
r + s = 13 rs = -30
Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C
r = \frac{13}{2} - u s = \frac{13}{2} + u
Two numbers r and s sum up to 13 exactly when the average of the two numbers is \frac{1}{2}*13 = \frac{13}{2}. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>
(\frac{13}{2} - u) (\frac{13}{2} + u) = -30
To solve for unknown quantity u, substitute these in the product equation rs = -30
\frac{169}{4} - u^2 = -30
Simplify by expanding (a -b) (a + b) = a^2 – b^2
-u^2 = -30-\frac{169}{4} = -\frac{289}{4}
Simplify the expression by subtracting \frac{169}{4} on both sides
u^2 = \frac{289}{4} u = \pm\sqrt{\frac{289}{4}} = \pm \frac{17}{2}
Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u
r =\frac{13}{2} - \frac{17}{2} = -2 s = \frac{13}{2} + \frac{17}{2} = 15
The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.