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m\left(m-10\right)=0
Factor out m.
m=0 m=10
To find equation solutions, solve m=0 and m-10=0.
m^{2}-10m=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
m=\frac{-\left(-10\right)±\sqrt{\left(-10\right)^{2}}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, -10 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
m=\frac{-\left(-10\right)±10}{2}
Take the square root of \left(-10\right)^{2}.
m=\frac{10±10}{2}
The opposite of -10 is 10.
m=\frac{20}{2}
Now solve the equation m=\frac{10±10}{2} when ± is plus. Add 10 to 10.
m=10
Divide 20 by 2.
m=\frac{0}{2}
Now solve the equation m=\frac{10±10}{2} when ± is minus. Subtract 10 from 10.
m=0
Divide 0 by 2.
m=10 m=0
The equation is now solved.
m^{2}-10m=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
m^{2}-10m+\left(-5\right)^{2}=\left(-5\right)^{2}
Divide -10, the coefficient of the x term, by 2 to get -5. Then add the square of -5 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
m^{2}-10m+25=25
Square -5.
\left(m-5\right)^{2}=25
Factor m^{2}-10m+25. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(m-5\right)^{2}}=\sqrt{25}
Take the square root of both sides of the equation.
m-5=5 m-5=-5
Simplify.
m=10 m=0
Add 5 to both sides of the equation.