Solve m/1/8=4/3x+1

$$m / \frac { 1 } { 8 } = \frac { 4 } { 3 x } + 1$$

Solve for m

$$m=\frac{1}{8}+\frac{1}{6x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

The equation is in standard form.

$$8m=1+\frac{4}{3x}$$

Divide both sides by 8.

$$\frac{8m}{8}=\frac{1+\frac{4}{3x}}{8}$$

Dividing by 8 undoes the multiplication by 8.

$$m=\frac{1+\frac{4}{3x}}{8}$$

Divide 1+\frac{4}{3x} by 8.

$$m=\frac{1}{8}+\frac{1}{6x}$$

Solve for x

$$x=-\frac{4}{3\left(1-8m\right)}$$

$$m\neq \frac{1}{8}$$

Steps for Solving Linear Equation

Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 3x.

$$3x\times \frac{m}{\frac{1}{8}}=4+3x$$

Subtract 3x from both sides.

$$3x\times \frac{m}{\frac{1}{8}}-3x=4$$

Combine all terms containing x.

$$\left(3\times \frac{m}{\frac{1}{8}}-3\right)x=4$$

The equation is in standard form.

$$\left(24m-3\right)x=4$$

Divide both sides by 24m-3.

$$\frac{\left(24m-3\right)x}{24m-3}=\frac{4}{24m-3}$$

Dividing by 24m-3 undoes the multiplication by 24m-3.

$$x=\frac{4}{24m-3}$$

Divide 4 by 24m-3.

$$x=\frac{4}{3\left(8m-1\right)}$$

Variable x cannot be equal to 0.

$$x=\frac{4}{3\left(8m-1\right)}\text{, }x\neq 0$$