Solve kx^2-12x-36=0h

$$k x ^ { 2 } - 12 x - 36 = 0 h$$

Solve for k

$$k=\frac{12\left(x+3\right)}{x^{2}}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Anything times zero gives zero.

$$kx^{2}-12x-36=0$$

Add 12x to both sides. Anything plus zero gives itself.

$$kx^{2}-36=12x$$

Add 36 to both sides.

$$kx^{2}=12x+36$$

The equation is in standard form.

$$x^{2}k=12x+36$$

Divide both sides by x^{2}.

$$\frac{x^{2}k}{x^{2}}=\frac{12x+36}{x^{2}}$$

Dividing by x^{2} undoes the multiplication by x^{2}.

$$k=\frac{12x+36}{x^{2}}$$

Divide 36+12x by x^{2}.

$$k=\frac{12\left(x+3\right)}{x^{2}}$$

Solve for h (complex solution)

$$h\in \mathrm{C}$$

$$k=\frac{12\left(x+3\right)}{x^{2}}\text{ and }x\neq 0$$

Solve for h

$$h\in \mathrm{R}$$

$$k=\frac{12\left(x+3\right)}{x^{2}}\text{ and }x\neq 0$$