Solve for k
k=2+\frac{3}{x}
x\neq 0
Solve for x
x=\frac{3}{k-2}
k\neq 2
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xk=2x+3
The equation is in standard form.
\frac{xk}{x}=\frac{2x+3}{x}
Divide both sides by x.
k=\frac{2x+3}{x}
Dividing by x undoes the multiplication by x.
k=2+\frac{3}{x}
Divide 2x+3 by x.
kx-2x=3
Subtract 2x from both sides.
\left(k-2\right)x=3
Combine all terms containing x.
\frac{\left(k-2\right)x}{k-2}=\frac{3}{k-2}
Divide both sides by k-2.
x=\frac{3}{k-2}
Dividing by k-2 undoes the multiplication by k-2.
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