Solve for k
k=-2+\frac{5}{x}
x\neq 0
Solve for x
x=\frac{5}{k+2}
k\neq -2
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kx=5-2x
Subtract 2x from both sides.
xk=5-2x
The equation is in standard form.
\frac{xk}{x}=\frac{5-2x}{x}
Divide both sides by x.
k=\frac{5-2x}{x}
Dividing by x undoes the multiplication by x.
k=-2+\frac{5}{x}
Divide 5-2x by x.
\left(k+2\right)x=5
Combine all terms containing x.
\frac{\left(k+2\right)x}{k+2}=\frac{5}{k+2}
Divide both sides by k+2.
x=\frac{5}{k+2}
Dividing by k+2 undoes the multiplication by k+2.
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