Solve k_{c}=(0.032)^2+(9032)^2/(0.0156)^4+(0.0840)

$$k _ { c } = \frac { ( 0.032 ) ^ { 2 } + ( 9032 ) ^ { 2 } } { ( 0.0156 ) ^ { 4 } + ( 0.0840 ) }$$

Solve for k_c

$$k_{c} = \frac{3186602500040000000000}{3281252313441} = 971154362\frac{3019181370502}{3281252313441} \approx 971154362.920130893$$

Steps for Solving Linear Equation

Calculate 0.032 to the power of 2 and get 0.001024.

$$k_{c}=\frac{0.001024+9032^{2}}{0.0156^{4}+0.084}$$

Calculate 9032 to the power of 2 and get 81577024.

$$k_{c}=\frac{0.001024+81577024}{0.0156^{4}+0.084}$$

Add 0.001024 and 81577024 to get 81577024.001024.

$$k_{c}=\frac{81577024.001024}{0.0156^{4}+0.084}$$

Calculate 0.0156 to the power of 4 and get 0.0000000592240896.

$$k_{c}=\frac{81577024.001024}{0.0000000592240896+0.084}$$

Add 0.0000000592240896 and 0.084 to get 0.0840000592240896.

$$k_{c}=\frac{81577024.001024}{0.0840000592240896}$$

Expand \frac{81577024.001024}{0.0840000592240896} by multiplying both numerator and the denominator by 10000000000000000.

$$k_{c}=\frac{815770240010240000000000}{840000592240896}$$

Reduce the fraction \frac{815770240010240000000000}{840000592240896} to lowest terms by extracting and canceling out 256.

$$k_{c}=\frac{3186602500040000000000}{3281252313441}$$

Assign k_c

$$k_{c}≔\frac{3186602500040000000000}{3281252313441}$$