Solve k|1+1

$$k | 1 + 1$$

Evaluate

$$2k$$

Solution Steps

Add 1 and 1 to get 2.

$$k|2|$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of 2 is 2.

$$k\times 2$$

Differentiate w.r.t. k

$$2$$

Steps Using Definition of a Derivative

Add 1 and 1 to get 2.

$$\frac{\mathrm{d}}{\mathrm{d}k}(k|2|)$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of 2 is 2.

$$\frac{\mathrm{d}}{\mathrm{d}k}(k\times 2)$$

The derivative of ax^{n} is nax^{n-1}.

$$2k^{1-1}$$

Subtract 1 from 1.

$$2k^{0}$$

For any term t except 0, t^{0}=1.

$$2\times 1$$

For any term t, t\times 1=t and 1t=t.

$$2$$