Solve k2^2+2*2-3

$$k { 2 }^{ 2 } +2 \times 2-3$$

Evaluate

$$4k+1$$

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$k\times 4+2\times 2-3$$

Multiply 2 and 2 to get 4.

$$k\times 4+4-3$$

Subtract 3 from 4 to get 1.

$$k\times 4+1$$

Differentiate w.r.t. k

$$4$$

Steps Using Derivative Rule for Sum

Calculate 2 to the power of 2 and get 4.

$$\frac{\mathrm{d}}{\mathrm{d}k}(k\times 4+2\times 2-3)$$

Multiply 2 and 2 to get 4.

$$\frac{\mathrm{d}}{\mathrm{d}k}(k\times 4+4-3)$$

Subtract 3 from 4 to get 1.

$$\frac{\mathrm{d}}{\mathrm{d}k}(k\times 4+1)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$4k^{1-1}$$

Subtract 1 from 1.

$$4k^{0}$$

For any term t except 0, t^{0}=1.

$$4\times 1$$

For any term t, t\times 1=t and 1t=t.

$$4$$