Solve kquad4(5-1)=5+a

$$k \quad 4 ( 5 - 1 ) = 5 + a$$

Solve for a

$$a=4k_{4}-5$$

Solution Steps

Subtract 1 from 5 to get 4.

$$k_{4}\times 4=5+a$$

Swap sides so that all variable terms are on the left hand side.

$$5+a=k_{4}\times 4$$

Subtract 5 from both sides.

$$a=k_{4}\times 4-5$$

Solve for k_4

$$k_{4}=\frac{a+5}{4}$$

Steps for Solving Linear Equation

Subtract 1 from 5 to get 4.

$$k_{4}\times 4=5+a$$

The equation is in standard form.

$$4k_{4}=a+5$$

Divide both sides by 4.

$$\frac{4k_{4}}{4}=\frac{a+5}{4}$$

Dividing by 4 undoes the multiplication by 4.

$$k_{4}=\frac{a+5}{4}$$