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t^{2}-7t+10=0
Substitute t for k^{2}.
t=\frac{-\left(-7\right)±\sqrt{\left(-7\right)^{2}-4\times 1\times 10}}{2}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Substitute 1 for a, -7 for b, and 10 for c in the quadratic formula.
t=\frac{7±3}{2}
Do the calculations.
t=5 t=2
Solve the equation t=\frac{7±3}{2} when ± is plus and when ± is minus.
k=\sqrt{5} k=-\sqrt{5} k=\sqrt{2} k=-\sqrt{2}
Since k=t^{2}, the solutions are obtained by evaluating k=±\sqrt{t} for each t.