Solve k^2-6x-7=0

$$k ^ { 2 } - 6 x - 7 = 0$$

Solve for x

$$x=\frac{k^{2}-7}{6}$$

Steps for Solving Linear Equation

Subtract k^{2} from both sides. Anything subtracted from zero gives its negation.

$$-6x-7=-k^{2}$$

Add 7 to both sides.

$$-6x=-k^{2}+7$$

The equation is in standard form.

$$-6x=7-k^{2}$$

Divide both sides by -6.

$$\frac{-6x}{-6}=\frac{7-k^{2}}{-6}$$

Dividing by -6 undoes the multiplication by -6.

$$x=\frac{7-k^{2}}{-6}$$

Divide -k^{2}+7 by -6.

$$x=\frac{k^{2}-7}{6}$$

Solve for k (complex solution)

$$k=-\sqrt{6x+7}$$

$$k=\sqrt{6x+7}$$

Solve for k

$$k=\sqrt{6x+7}$$

$$k=-\sqrt{6x+7}\text{, }x\geq -\frac{7}{6}$$