Solve for k
k\in (-\infty,-2\sqrt{6}]\cup [2\sqrt{6},\infty)
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k^{2}\geq 24
Add 24 to both sides.
k^{2}\geq \left(2\sqrt{6}\right)^{2}
Calculate the square root of 24 and get 2\sqrt{6}. Rewrite 24 as \left(2\sqrt{6}\right)^{2}.
|k|\geq 2\sqrt{6}
Inequality holds for |k|\geq 2\sqrt{6}.
k\leq -2\sqrt{6}\text{; }k\geq 2\sqrt{6}
Rewrite |k|\geq 2\sqrt{6} as k\leq -2\sqrt{6}\text{; }k\geq 2\sqrt{6}.
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