Solve for k
k\in (-\infty,-\sqrt{13}]\cup [\sqrt{13},\infty)
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k^{2}\geq 13
Add 13 to both sides.
k^{2}\geq \left(\sqrt{13}\right)^{2}
Calculate the square root of 13 and get \sqrt{13}. Rewrite 13 as \left(\sqrt{13}\right)^{2}.
|k|\geq \sqrt{13}
Inequality holds for |k|\geq \sqrt{13}.
k\leq -\sqrt{13}\text{; }k\geq \sqrt{13}
Rewrite |k|\geq \sqrt{13} as k\leq -\sqrt{13}\text{; }k\geq \sqrt{13}.
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