Solve k^2-11k-102

$$k ^ { 2 } - 11 k - 102$$

Factor

$$\left(k-17\right)\left(k+6\right)$$

Solution Steps

Factor the expression by grouping. First, the expression needs to be rewritten as k^{2}+ak+bk-102. To find a and b, set up a system to be solved.

$$a+b=-11 ab=1\left(-102\right)=-102$$

Since ab is negative, a and b have the opposite signs. Since a+b is negative, the negative number has greater absolute value than the positive. List all such integer pairs that give product -102.

$$1,-102 2,-51 3,-34 6,-17$$

Calculate the sum for each pair.

$$1-102=-101 2-51=-49 3-34=-31 6-17=-11$$

The solution is the pair that gives sum -11.

$$a=-17 b=6$$

Rewrite k^{2}-11k-102 as \left(k^{2}-17k\right)+\left(6k-102\right).

$$\left(k^{2}-17k\right)+\left(6k-102\right)$$

Factor out k in the first and 6 in the second group.

$$k\left(k-17\right)+6\left(k-17\right)$$

Factor out common term k-17 by using distributive property.

$$\left(k-17\right)\left(k+6\right)$$

Steps Using the Quadratic Formula

Quadratic polynomial can be factored using the transformation ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), where x_{1} and x_{2} are the solutions of the quadratic equation ax^{2}+bx+c=0.

$$k^{2}-11k-102=0$$

All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.

$$k=\frac{-\left(-11\right)±\sqrt{\left(-11\right)^{2}-4\left(-102\right)}}{2}$$

Square -11.

$$k=\frac{-\left(-11\right)±\sqrt{121-4\left(-102\right)}}{2}$$

Multiply -4 times -102.

$$k=\frac{-\left(-11\right)±\sqrt{121+408}}{2}$$

Add 121 to 408.

$$k=\frac{-\left(-11\right)±\sqrt{529}}{2}$$

Take the square root of 529.

$$k=\frac{-\left(-11\right)±23}{2}$$

The opposite of -11 is 11.

$$k=\frac{11±23}{2}$$

Now solve the equation k=\frac{11±23}{2} when ± is plus. Add 11 to 23.

$$k=\frac{34}{2}$$

Divide 34 by 2.

$$k=17$$

Now solve the equation k=\frac{11±23}{2} when ± is minus. Subtract 23 from 11.

$$k=-\frac{12}{2}$$

Divide -12 by 2.

$$k=-6$$

Factor the original expression using ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Substitute 17 for x_{1} and -6 for x_{2}.

$$k^{2}-11k-102=\left(k-17\right)\left(k-\left(-6\right)\right)$$

Simplify all the expressions of the form p-\left(-q\right) to p+q.

$$k^{2}-11k-102=\left(k-17\right)\left(k+6\right)$$

Steps Using Direct Factoring Method

Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.

$$x ^ 2 -11x -102 = 0$$

Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C

$$r + s = 11 rs = -102$$

Two numbers r and s sum up to 11 exactly when the average of the two numbers is \frac{1}{2}*11 = \frac{11}{2}. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>

$$r = \frac{11}{2} - u s = \frac{11}{2} + u$$

To solve for unknown quantity u, substitute these in the product equation rs = -102

$$(\frac{11}{2} - u) (\frac{11}{2} + u) = -102$$

Simplify by expanding (a -b) (a + b) = a^2 – b^2

$$\frac{121}{4} - u^2 = -102$$

Simplify the expression by subtracting \frac{121}{4} on both sides

$$-u^2 = -102-\frac{121}{4} = -\frac{529}{4}$$

Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u

$$u^2 = \frac{529}{4} u = \pm\sqrt{\frac{529}{4}} = \pm \frac{23}{2}$$

The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.

$$r =\frac{11}{2} - \frac{23}{2} = -6 s = \frac{11}{2} + \frac{23}{2} = 17$$

Evaluate

$$\left(k-17\right)\left(k+6\right)$$