Solve k^2=sqrt{9}-7[g]

$$k ^ { 2 } = \sqrt { 9 } - 7 [ g ]$$

Solve for g

$$g=\frac{3-k^{2}}{7}$$

Steps for Solving Linear Equation

Calculate the square root of 9 and get 3.

$$k^{2}=3-7g$$

Swap sides so that all variable terms are on the left hand side.

$$3-7g=k^{2}$$

Subtract 3 from both sides.

$$-7g=k^{2}-3$$

Divide both sides by -7.

$$\frac{-7g}{-7}=\frac{k^{2}-3}{-7}$$

Dividing by -7 undoes the multiplication by -7.

$$g=\frac{k^{2}-3}{-7}$$

Divide k^{2}-3 by -7.

$$g=\frac{3-k^{2}}{7}$$

Solve for k

$$k=\sqrt{3-7g}$$

$$k=-\sqrt{3-7g}\text{, }g\leq \frac{3}{7}$$