Solve k=80*(10*34-30*6)^2/40*40*16*64

$$k = \frac { 80 \times ( 10 \times 34 - 30 \times 6 ) ^ { 2 } } { 40 \times 40 \times 16 \times 64 }$$

Solve for k

$$k = \frac{5}{4} = 1\frac{1}{4} = 1.25$$

Steps for Solving Linear Equation

Cancel out 2\times 40 in both numerator and denominator.

$$k=\frac{\left(10\times 34-6\times 30\right)^{2}}{16\times 20\times 64}$$

Multiply 10 and 34 to get 340.

$$k=\frac{\left(340-6\times 30\right)^{2}}{16\times 20\times 64}$$

Multiply 6 and 30 to get 180.

$$k=\frac{\left(340-180\right)^{2}}{16\times 20\times 64}$$

Subtract 180 from 340 to get 160.

$$k=\frac{160^{2}}{16\times 20\times 64}$$

Calculate 160 to the power of 2 and get 25600.

$$k=\frac{25600}{16\times 20\times 64}$$

Multiply 16 and 20 to get 320.

$$k=\frac{25600}{320\times 64}$$

Multiply 320 and 64 to get 20480.

$$k=\frac{25600}{20480}$$

Reduce the fraction \frac{25600}{20480} to lowest terms by extracting and canceling out 5120.

$$k=\frac{5}{4}$$

Assign k

$$k≔\frac{5}{4}$$