Solve j+5/12<-3/4*3

$$j + \frac { 5 } { 12 } < - \frac { 3 } { 4 } \times 3$$

Solve for j

$$j<-\frac{8}{3}$$

Solution Steps

Express -\frac{3}{4}\times 3 as a single fraction.

$$j+\frac{5}{12}<\frac{-3\times 3}{4}$$

Multiply -3 and 3 to get -9.

$$j+\frac{5}{12}<\frac{-9}{4}$$

Fraction \frac{-9}{4} can be rewritten as -\frac{9}{4} by extracting the negative sign.

$$j+\frac{5}{12}<-\frac{9}{4}$$

Subtract \frac{5}{12} from both sides.

$$j<-\frac{9}{4}-\frac{5}{12}$$

Least common multiple of 4 and 12 is 12. Convert -\frac{9}{4} and \frac{5}{12} to fractions with denominator 12.

$$j<-\frac{27}{12}-\frac{5}{12}$$

Since -\frac{27}{12} and \frac{5}{12} have the same denominator, subtract them by subtracting their numerators.

$$j<\frac{-27-5}{12}$$

Subtract 5 from -27 to get -32.

$$j<\frac{-32}{12}$$

Reduce the fraction \frac{-32}{12} to lowest terms by extracting and canceling out 4.

$$j<-\frac{8}{3}$$