Solve if:x=y+3

$$i f : x = y + 3$$

Solve for f

$$f=-ix\left(y+3\right)$$

$$x\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by x.

$$if=xy+x\times 3$$

The equation is in standard form.

$$if=xy+3x$$

Divide both sides by i.

$$\frac{if}{i}=\frac{x\left(y+3\right)}{i}$$

Dividing by i undoes the multiplication by i.

$$f=\frac{x\left(y+3\right)}{i}$$

Divide x\left(3+y\right) by i.

$$f=-ix\left(y+3\right)$$

Solve for x

$$\left\{\begin{matrix}x=-\frac{f}{iy+3i}\text{, }&f\neq 0\text{ and }y\neq -3\\x\neq 0\text{, }&y=-3\text{ and }f=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by x.

$$if=xy+x\times 3$$

Swap sides so that all variable terms are on the left hand side.

$$xy+x\times 3=if$$

Combine all terms containing x.

$$\left(y+3\right)x=if$$

Divide both sides by 3+y.

$$\frac{\left(y+3\right)x}{y+3}=\frac{if}{y+3}$$

Dividing by 3+y undoes the multiplication by 3+y.

$$x=\frac{if}{y+3}$$

Variable x cannot be equal to 0.

$$x=\frac{if}{y+3}\text{, }x\neq 0$$