Solve ib=7*(-3)+(-8)^2:(+2)^5-13

$$i b = 7 \cdot ( - 3 ) + ( - 8 ) ^ { 2 } : ( + 2 ) ^ { 5 } - 13$$

Solve for b

$$b=32i$$

Steps for Solving Linear Equation

Multiply 7 and -3 to get -21.

$$ib=-21+\frac{\left(-8\right)^{2}}{2^{5}}-13$$

Calculate -8 to the power of 2 and get 64.

$$ib=-21+\frac{64}{2^{5}}-13$$

Calculate 2 to the power of 5 and get 32.

$$ib=-21+\frac{64}{32}-13$$

Divide 64 by 32 to get 2.

$$ib=-21+2-13$$

Add -21 and 2 to get -19.

$$ib=-19-13$$

Subtract 13 from -19 to get -32.

$$ib=-32$$

Divide both sides by i.

$$b=\frac{-32}{i}$$

Multiply both numerator and denominator of \frac{-32}{i} by imaginary unit i.

$$b=\frac{-32i}{1i^{2}}$$

By definition, i^{2} is -1. Calculate the denominator.

$$b=\frac{-32i}{-1}$$

Divide -32i by -1 to get 32i.

$$b=32i$$