Solve i|-37:(1)(sqrt{6}+sqrt{6})^2=

$$i | - 37 : ( 1 ) ( \sqrt { 6 } + \sqrt { 6 } ) ^ { 2 } =$$

Evaluate

$$888i$$

Solution Steps

Anything divided by one gives itself.

$$i|-37\left(\sqrt{6}+\sqrt{6}\right)^{2}|$$

Combine \sqrt{6} and \sqrt{6} to get 2\sqrt{6}.

$$i|-37\times \left(2\sqrt{6}\right)^{2}|$$

Expand \left(2\sqrt{6}\right)^{2}.

$$i|-37\times 2^{2}\left(\sqrt{6}\right)^{2}|$$

Calculate 2 to the power of 2 and get 4.

$$i|-37\times 4\left(\sqrt{6}\right)^{2}|$$

The square of \sqrt{6} is 6.

$$i|-37\times 4\times 6|$$

Multiply 4 and 6 to get 24.

$$i|-37\times 24|$$

Multiply -37 and 24 to get -888.

$$i|-888|$$

The modulus of a complex number a+bi is \sqrt{a^{2}+b^{2}}. The modulus of -888 is 888.

$$888i$$

Real Part

$$0$$

Solution Steps

Anything divided by one gives itself.

$$Re(i|-37\left(\sqrt{6}+\sqrt{6}\right)^{2}|)$$

Combine \sqrt{6} and \sqrt{6} to get 2\sqrt{6}.

$$Re(i|-37\times \left(2\sqrt{6}\right)^{2}|)$$

Expand \left(2\sqrt{6}\right)^{2}.

$$Re(i|-37\times 2^{2}\left(\sqrt{6}\right)^{2}|)$$

Calculate 2 to the power of 2 and get 4.

$$Re(i|-37\times 4\left(\sqrt{6}\right)^{2}|)$$

The square of \sqrt{6} is 6.

$$Re(i|-37\times 4\times 6|)$$

Multiply 4 and 6 to get 24.

$$Re(i|-37\times 24|)$$

Multiply -37 and 24 to get -888.

$$Re(i|-888|)$$

The modulus of a complex number a+bi is \sqrt{a^{2}+b^{2}}. The modulus of -888 is 888.

$$Re(888i)$$

The real part of 888i is 0.

$$0$$