Evaluate
3\left(x+\sqrt{3}\right)^{2}-11
Expand
3x^{2}+6\sqrt{3}x-2
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\left(\sqrt{3}\right)^{2}x^{2}+6\sqrt{3}x+9-11
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(\sqrt{3}x+3\right)^{2}.
3x^{2}+6\sqrt{3}x+9-11
The square of \sqrt{3} is 3.
3x^{2}+6\sqrt{3}x-2
Subtract 11 from 9 to get -2.
\left(\sqrt{3}\right)^{2}x^{2}+6\sqrt{3}x+9-11
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(\sqrt{3}x+3\right)^{2}.
3x^{2}+6\sqrt{3}x+9-11
The square of \sqrt{3} is 3.
3x^{2}+6\sqrt{3}x-2
Subtract 11 from 9 to get -2.
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