Solve for g
g=\frac{h-f^{2}}{2}
Solve for f
f=\sqrt{h-2g}
f=-\sqrt{h-2g}\text{, }h\geq 2g
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f^{2}+2g=h
Swap sides so that all variable terms are on the left hand side.
2g=h-f^{2}
Subtract f^{2} from both sides.
\frac{2g}{2}=\frac{h-f^{2}}{2}
Divide both sides by 2.
g=\frac{h-f^{2}}{2}
Dividing by 2 undoes the multiplication by 2.
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