Solve for h
h=23-2t^{2}
Solve for t
t=\frac{\sqrt{46-2h}}{2}
t=-\frac{\sqrt{46-2h}}{2}\text{, }h\leq 23
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h=-2t^{2}+0+23
Anything times zero gives zero.
h=-2t^{2}+23
Add 0 and 23 to get 23.
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