Solve h=frac{sqrt{3x}}{2}

$$h = \frac { \sqrt { 3 x } } { 2 }$$

Solve for x

$$x=\frac{4h^{2}}{3}$$

$$h\geq 0$$

Steps for Solving Radical Equations

Swap sides so that all variable terms are on the left hand side.

$$\frac{\sqrt{3x}}{2}=h$$

Multiply both sides by 2.

$$\frac{\frac{1}{2}\sqrt{3x}}{\frac{1}{2}}=\frac{h}{\frac{1}{2}}$$

Dividing by \frac{1}{2} undoes the multiplication by \frac{1}{2}.

$$\sqrt{3x}=\frac{h}{\frac{1}{2}}$$

Divide h by \frac{1}{2} by multiplying h by the reciprocal of \frac{1}{2}.

$$\sqrt{3x}=2h$$

Square both sides of the equation.

$$3x=4h^{2}$$

Divide both sides by 3.

$$\frac{3x}{3}=\frac{4h^{2}}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$x=\frac{4h^{2}}{3}$$

Solve for x (complex solution)

$$x=\frac{4h^{2}}{3}$$

$$|\frac{arg(h^{2})}{2}-arg(h)|<\pi \text{ or }h=0$$

Solve for h

$$h=\frac{\sqrt{3x}}{2}$$

$$x\geq 0$$